Sour a bets is by definition a bet on which the player is on gaining. That is possible when the odds of the events checks a certain relation. Which is this magic relation? One will note C (E) the odd of the event E and M (E) the setting deposited by the player on the event E. The player will be gaining if the sum of its profits exceeds the sum of its settings. The sum of the profits is in fact produces it M (E) * C (E) where E indicates the gaining event. As one does not know by definition not in advance which will be E, it is thus necessary that some is E, M (E) *C (E) > ∑ M (E). Let us apply this system of inequation to the two most frequent cases: a match necessarily designating a winner among two adversaries, and the case of a match where a tie can occur.
For the case of the match with two odds, there are thus the two following inequations: M (1) *C (1) > M (1) +M (2) and M (2) *C (2) > M (1) +M (2). One can rewrite these inequations as follows: C (1) > 1 + M (2) /M (1) and C (2) > 1 + M (1) /M (2). Let us rewrite by expressing the condition on the report/ratio M (1) /M (2): M (1) /M (2) > 1/(C (1) - 1) and M (1) /M (2) < C=""> 1/(C (1) - 1). Let us reexpress this condition: (C (1) - 1) * (C (2) - 1) > 1. By dividing by the product C (1) *C (2), one can express the inequation as follows: 1/C (1) + 1/C (2) < 1.
Let us take an example to illustrate the matter. Let us imagine the match of tennis shoe between the United States and Spain. The team of the United States sees itself affecting the odd of 1.90 while Spain obtains odd 2,20. Concretely that means that if player bets 10 € on the United States and that the Americans gain, it will empochera 19 €. The same if Spain carries it and that it put above 10 €, it will touch 22 €. The more the bookmaker considers that the event has chances to occur, the more it will allot a weak odd to him, and conversely. The previously given magic formula gives an evaluation of 1/1.90 + 1/2.20 = 0.98 < 1. Now an example with three possible events. A football game opposes France to Canada. The odds are the following ones: 1,90 for a victory of France, 6.00 for a victory of Canada and 3.40 for a tie. The formula gives 1/1.90 + 1/6 + 1/3.40 = 0.99 < 1.

For further going and seeing how the settings are defined, it is first of all necessary to know to find these sour bets. Soyonr realistic: do not wait especially until a bookmaker proposes to you on a match of the odds which would correspond to sour a bets! The easy way consists with miser on the same match on which bets would be open in several bookmakers, with different odds. Indeed all the bookmakers necessarily in the same way will not evaluate the chances of the adversaries. In our example of match of tennis shoe between the United States and Spain, one can imagine that a second bookmaker could give much less chance to Spain to gain, and thus to increase his odd and decrease that of the United States. That remains an academic case, it is rare that bookmakers have an opinion completely opposed on the involved forces. However there can be nuances likely to make it possible to establish sour a bets. In our example, if a bookmaker gives a odd of 1.90 to the United States and 2.10 in Spain, and if a second bookmaker allot repectives odds of 1.80 and 2.20 to them, none of them proposes sour a bets (1/1.90 + 1/2.10 = 1.0025 > 1 and 1/1.80 + 1/2.20 = 1.01 > 1). On the other hand by using the odd of the first on the United States and that of the second on Spain, one obtains sour a bets (1/1.90 + 1/2.20 = 0.98 < 1.
Consequently, how to know these sour bets without having to calculate all the combinations? An Internet site takes care some already: oddsexchange.com. The site is unfortunately in English, but quality is with return to you. A list of sour the bets is proposed with the list of the matches concerned and the bookmakers proposing the odds corresponding to sour the bets. The free version gives access to some sour bets each day. Well more are proposed with the paying version.

Now that you can recognize sour the bets and where to find them, it is necessary for you now to learn how to benefit from it. It was seen previously that the conditions of sour the bets were controls by inequations, which means that several settings can be appropriate. This stage one will add an additional condition to define single settings on each event: one will seek to obtain the same benefit, some is the event.
The condition of equality of the profits some is the result gives: M (1) *C (1) = M (2) *C (2). One from of deduced: M (2) = M (1) *C (1) /C (2). You can choose with your own way the value of M (1). It will condition by this equation that of M (2). The profit is calculated as follows: M (1) *C (1) - (M (1) +M (2)) = M (1) * (C (1) - 1-C (1) /C (2)). For a match of the 1N2 type, in the same way, M (2) = M (1) *C (1) /C (2) and M (NR) = M (1) *C (1) /C (NR). The profit will be of: M (1) * (C (1) - 1-C (1) /C (2) - C (1) /C (NR)).

Sour the bets thus seems an average ideal to place its money with an output of some pourcents each day! Unfortunately the things are not as ideal as they can seem it. First of all it is necessary to be very vigilent on the announced odds. They can possibly be readjusted and you will have each time to make sure that they are fixed until the designation of the result. The other difficulty to apply sour the bets is the fact owe miser on in several bookmakers. But the main issue is related to the expenses supported at the time of the banking transactions. These expenses will be all the more problematic as you will be brought to use various bookmakers.
Ultimately if you wish to use sour the bets, made with full knowledge of the facts and take well into account the ancillary costs which you will have to support.

To carry out sporting bets, let use the frequently asked questions about sporting bets. To find the bookmaker on Internet which best corresponds to you, the online bookmakers search engine or sportsbooks sites list : A-L / M-Z.